Jambmaths question:
In how many ways can 2 students be seated from a group of 5 students in a debating competition?
Option A:
10 ways
Option B:
15 ways
Option C:
25 ways
Option D:
20 ways
Jamb Maths Solution:
The number of possible selection $^{5}{{C}_{2}}=\frac{5!}{(5-2)!2!}=\frac{5!}{3!2!}=\frac{5\times 4\times 3!}{3!\times 2\times 1}=10ways$
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