Jambmaths question:
The slope of the tangent to the curve $y=3{{x}^{2}}-2x+5$ at the point (1,6) is
Option A:
4
Option B:
1
Option C:
6
Option D:
5
Jamb Maths Solution:
$\begin{align} & y=3{{x}^{2}}-2x+5 \\ & \frac{dy}{dx}=6x-2 \\ & \text{Note }\frac{dy}{dx}\text{ is the slope of the tangent, so at point (1,6)} \\ & \frac{dy}{dx}\left| _{(1,6)} \right.=6(1)-2=4 \\\end{align}$
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