Jambmaths question:
A chord of a circle of radius $\sqrt{6}cm$subtends an angle of 30oon the circumference of circle. Find the length of the chord
Option A:
$2\sqrt{6}$
Option B:
$3\sqrt{2}$
Option C:
$\sqrt{6}$
Option D:
$2\sqrt{3}$
Jamb Maths Solution:
$\begin{align} & \left| AD \right|=\left| AO \right|\cos {{30}^{\circ }}=\sqrt{6}\times \frac{\sqrt{3}}{2}=\frac{3\sqrt{2}}{2} \\ & \left| AB \right|=2\left| AD \right|=2\times \frac{3\sqrt{2}}{2}=3\sqrt{2}cm \\\end{align}$
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