Jambmaths question:
A binary operation * is defined by $x*y={{x}^{y}}$ . If $x*2=12-x$ find the possible value of x
Option A:
–3, 4
Option B:
–3, –4
Option C:
3, 4
Option D:
3, –4
Jamb Maths Solution:
$\begin{align} & x*2=12-x \\ & {{x}^{2}}=12-x \\ & {{x}^{2}}+x-12=0 \\ & (x+4)(x-3)=0 \\ & x=-4\text{ or }x=3 \\\end{align}$
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