Jambmaths question:
Factorize $4{{x}^{2}}-9{{y}^{2}}+20x+25$
Option A:
(2x – 3y +5) (2x – 3y –5)
Option B:
(2x – 3y)(2x + 3y)
Option C:
(2x – 3y +5) (2x + 3y + 5)
Option D:
(2x + 5) (2x – 9y –5)
Jamb Maths Solution:
$\begin{align} & 4{{x}^{2}}-9{{y}^{2}}+20x+25=4{{x}^{2}}+20x+25-9{{y}^{2}} \\ & =4{{x}^{2}}+10x+10x+25-9{{y}^{2}} \\ & =(2x+5)(2x+5)-9{{y}^{2}} \\ & ={{(2x+5)}^{2}}-9{{y}^{2}} \\ & =(2x+5-3y)(2x+5+3y) \end{align}$
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