waecmaths question:
In the diagram O is the centre of the circle PQRS and $\angle PSR={{86}^{\circ }}$, if $\angle POR={{x}^{\circ }}$ find x
Option A:
274o
Option B:
172o
Option C:
129o
Option D:
86o
waecmaths solution:
$\begin{align} & \angle PSR={{86}^{\circ }} \\ & \angle POR=2\angle PSR\text{ }\!\!\{\!\!\text{ }\angle \text{ at centre is 2}\times \angle \text{ at cirum }\!\!\}\!\!\text{ } \\ & \angle POR=2\times {{86}^{\circ }}={{172}^{\circ }} \\ & x={{172}^{\circ }} \\\end{align}$
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