Jambmaths question:
Evaluate $\int_{-4}^{0}{(1-2x)dx}$
Option A:
–16
Option B:
20
Option C:
–20
Option D:
10
Jamb Maths Solution:
$\begin{align} & \int_{-4}^{0}{(1-2x)dx}=\left[ x-{{x}^{2}} \right]_{-4}^{0} \\ & =\left[ 0-0 \right]-\left[ (-4)-{{(-4)}^{2}} \right] \\ & =\left[ -4-16 \right]=-20 \end{align}$
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