$\begin{align}  & \text{Produce }GH\text{ to }C\text{ to meet }BE\text{ at point }D \\ & \angle CDE=\angle ABD={{110}^{\circ }}\text{   }\!\!\{\!\!\text{ corresponding }\angle s\} \\ & \angle DGF=\angle CDE={{110}^{\circ }}\text{ }\!\!\{\!\!\text{ corresponding }\angle s\} \\ & x={{180}^{\circ }}-\angle DGF\text{  }\!\!\{\!\!\text{ }\angle s\text{ in a }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & x={{180}^{\circ }}-{{110}^{\circ }}={{70}^{\circ }} \\\end{align}$