Jambmaths question:
The nth term of a sequence ${{n}^{2}}-6n-4$. Find the sum of the 3rd and 4th terms.
Option A:
24
Option B:
23
Option C:
–24
Option D:
– 25
Jamb Maths Solution:
$\begin{align} & {{n}^{th}}term={{n}^{2}}-6n-4 \\ & {{3}^{rd}}term={{3}^{2}}-6(3)-4=-13 \\ & {{4}^{th}}\text{ }term={{4}^{2}}-6(4)-4=-10 \\ & \text{Sum of }{{\text{3}}^{rd}}\text{ and }{{\text{4}}^{th}}\text{ term}=-13-10=-23 \\\end{align}$
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