Jambmaths question:
The nth term of the sequence $\tfrac{3}{2},3,7,16,35,74,-,-,-$ is
Option A:
$tfrac{3}{2}$
Option B:
$3\cdot {{2}^{n-2}}$
Option C:
$5\cdot {{2}^{n-2}}-\tfrac{n+1}{2}$
Option D:
$5\cdot {{2}^{n-2}}-n$
Jamb Maths Solution:
The best method and that would save time is to work from the options provided by substituting n = 1, 2, 3. By so doing you will discover that Option D is the correct option
Answer: Option D
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