
In the diagram, PS and RS are tangents to the circle centre O, $\angle PSR=70{}^\circ $, $\angle POR=m$and $\angle PQR=n$. Find (m + n)
110o
135o
165o
225o
$\begin{align} & \angle OPS=90{}^\circ \{\text{Tangent to a circle }\!\!\}\!\!\text{ } \\ & \angle ORS=90{}^\circ \{\text{Tangent to a circle }\!\!\}\!\!\text{ } \\ & \angle PQR+\angle OPS+\angle ORS+\angle PSR=360{}^\circ \\ & \{\text{Sum of }\angle s\text{ in quad}\text{. }\!\!\}\!\!\text{ } \\ & m+90{}^\circ +90{}^\circ +70{}^\circ =360{}^\circ \\ & m=110{}^\circ \\ & \angle PQR=\tfrac{1}{2}\angle PQR \\ & \{\angle \text{ at circum}\text{.}=2\times \angle \text{ at the centre }\!\!\}\!\!\text{ } \\ & n=\tfrac{1}{2}(110{}^\circ )=55{}^\circ \\ & m+n=110{}^\circ +55{}^\circ \\ & m+n=165{}^\circ \\\end{align}$
