Jambmaths question:
Solve the inequality 2 –x > x2
Option A:
$\text{ }x<-2,\text{ or }x>1$
Option B:
$x>2\text{ or }x<-1\text{ }$
Option C:
$-2<x<1$
Option D:
$-1<x<2\text{ }$
Jamb Maths Solution:
$\begin{align} & 2-x>{{x}^{2}} \\ & {{x}^{2}}+x-2<0 \\ & (x+2)(x-1)<0 \\ & x+2<0\text{ or }x-1<0 \\ & x<-2\text{ or }x<1 \\ & \text{The range valid from }-2\text{ to }1 \\ & -2<x<1 \\\end{align}$
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