Maths Question:
$\begin{align} & \text{Write down the general solution of the trigonometric equations} \\ & \cos (2\theta -{{30}^{\circ }})=0 \\\end{align}$
Maths Solution:
$\begin{align} & \cos (2\theta -{{30}^{\circ }})=0 \\ & 2\theta -{{30}^{\circ }}={{\cos }^{-1}}(0) \\ & 2\theta -{{30}^{\circ }}={{90}^{\circ }} \\ & \text{The general solution will be } \\ & 2\theta -{{30}^{\circ }}=n{{360}^{\circ }}\pm {{90}^{\circ }} \\ & \theta =\frac{[n{{360}^{\circ }}\pm {{90}^{\circ }}]+{{30}^{\circ }}}{2}=[n{{180}^{\circ }}\pm {{45}^{\circ }}]+{{15}^{\circ }} \\\end{align}$
University mathstopic: