Jambmaths question:
A box containing10 black, 4 green and 6 yellow pens. What is probability of picking a yellow pen with eyes closed
Option A:
$\tfrac{1}{5}$
Option B:
$\tfrac{7}{10}$
Option C:
$\tfrac{3}{10}$
Option D:
$\tfrac{1}{2}$
Jamb Maths Solution:
Total number of pens = 10 + 4 +6 =20
Number of yellow pens = 6
$\text{Probability =}\frac{\text{number of expected outcome}}{\text{total number of expected outcome}}$
$\Pr (Yellow)=\frac{6}{20}=\frac{3}{10}$
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