Jambmaths question:
The graph of the function $y={{x}^{2}}+4$and the straight line PQ are drawn to solve the equation ${{x}^{2}}-3x+2=0$. What is the equation PQ
Option A:
y = 3x +2
Option B:
y = –3x –2
Option C:
y = 3x – 4
Option D:
y=3x +4
Jamb Maths Solution:
$\begin{align} & \text{Let }{{x}^{2}}+4+{{y}_{1}}={{x}^{2}}-3x+2 \\ & {{y}_{1}}=-3x+2-4 \\ & {{y}_{1}}=-3x-2 \\\end{align}$
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