Jambmaths question:
Simplify $1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}$
Option A:
$4\tfrac{1}{3}$
Option B:
$4\tfrac{2}{3}$
Option C:
$4\tfrac{12}{17}$
Option D:
$4\tfrac{3}{17}$
Jamb Maths Solution:
$\begin{align} & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+\tfrac{17}{4}\div \tfrac{17}{12} \\ & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+\tfrac{17}{4}\times \tfrac{12}{17} \\ & 1\tfrac{2}{3}+4\tfrac{1}{4}\div 1\tfrac{5}{12}=\tfrac{5}{6}+3=\tfrac{23}{6} \\\end{align}$
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