Jambmaths question:
Factorize completely $9{{y}^{2}}-16{{x}^{2}}$
Option A:
$(3y+2x)(3y-4x)$
Option B:
$(3y+4x)(3y-4x)$
Option C:
$(3y+4x)(3y+4x)$
Option D:
$(3y-2x)(3y+4x)$
Jamb Maths Solution:
$9{{y}^{2}}-16{{x}^{2}}$is a difference of two squares
$9{{y}^{2}}-16{{x}^{2}}={{(3y)}^{2}}-{{(4x)}^{2}}=(3y+4x)(3y-4x)$
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