Jambmaths question:
Make Q the subject of the formula, when $L=\frac{4}{3}M\sqrt{PQ}$
Option A:
$\frac{9{{L}^{2}}}{16{{M}^{2}}P}$
Option B:
$\frac{3L}{4M\sqrt{P}}$
Option C:
$\frac{\sqrt{3L}}{4MP}$
Option D:
$\frac{3{{L}^{2}}}{16{{M}^{2}}P}$
Jamb Maths Solution:
$\begin{align} & L=\frac{4}{3}M\sqrt{PQ} \\ & \text{Multiply both sides by }\frac{3}{4M} \\ & \sqrt{PQ}=\frac{3L}{4M} \\ & \text{square both sides} \\ & PQ=\frac{9{{L}^{2}}}{16{{M}^{2}}} \\ & \text{Divide both sides by }P \\ & Q=\frac{9{{L}^{2}}}{16P{{M}^{2}}} \\\end{align}$
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