Jambmaths question:
Make n the subject of the formula if $w=\frac{v(2+cn)}{1-cn}$
Option A:
$\tfrac{1}{c}\left( \tfrac{w-2v}{v+w} \right)$
Option B:
$\tfrac{1}{c}\left( \tfrac{w-2v}{v-w} \right)$
Option C:
$\tfrac{1}{c}\left( \tfrac{w+2v}{v-w} \right)$
Option D:
$\tfrac{1}{c}\left( \tfrac{w+2v}{v+w} \right)$
Jamb Maths Solution:
$\begin{align} & w=\frac{v(2+cn)}{1-cn} \\ & \text{Mulitply both sides by (}1-cn\text{)} \\ & w(1-cn)=v(2+cn) \\ & w-wcn=2v+cvn \\ & w-2v=cvn+cwn \\ & w-2v=n(cv+cw) \\ & n=\frac{w-2v}{cv+cw}=\frac{w-2v}{c(v+w)}=\frac{1}{c}\left( \frac{w-2v}{v+w} \right) \\\end{align}$
Jamb Maths Topic:
Year of Exam: