Jambmaths question:
If $X=\{{{n}^{2}}+1:n=0,2,3\}$and $Y=\{n+1:n=2,3,5\}$ find $X\cap Y$
Option A:
{1, 3}
Option B:
{5, 10}
Option C:
$\varnothing $
Option D:
{4, 6}
Jamb Maths Solution:
$\begin{align} & X=\{1,5,10\} \\ & Y=\{3,4,6\} \\ & X\cap Y=\{\}\text{or }\varnothing \end{align}$
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