Question 1

Jambmaths question: 

Evaluate $1011_{2}^{2}-101_{2}^{2}$

Option A: 

1102

Option B: 

110002

Option C: 

1100002

Option D: 

11000002

Jamb Maths Solution: 

$\begin{align}  & 1011_{2}^{2}-101_{2}^{2}=({{1011}_{2}}-{{101}_{2}})({{1011}_{2}}+{{101}_{2}}) \\ & ={{110}_{2}}\times {{10000}_{2}} \\ & ={{1100000}_{2}} \\\end{align}$ 

Jamb Maths Topic: 
Number Base System
Year of Exam: 
Jamb Maths 2007